Solution:
[tex]\text{number of H atoms = 2 mol NH₃} × \frac{\text{3 mol H}}{\text{1 mol NH₃}} × \frac{\text{6.022 × 10²³ H atoms}}{\text{1 mol H}}[/tex]
[tex]\boxed{\text{number of H atoms = 3.61 × 10²⁴ atoms}}[/tex]
Answer:
The answer is C. 3.61 × 10²⁴ atoms
#CarryOnLearning
