Sagot :
[tex]\frac{2}{3}[/tex]
[tex]\frac{1}{6}[/tex] + [tex]\frac{3}{4}[/tex] = n
[tex]\frac{1}{6}[/tex] = [tex]\frac{2}{12}[/tex]
[tex]\frac{3}{4}[/tex] = [tex]\frac{6}{12}[/tex]
[tex]\frac{2}{12}[/tex] + [tex]\frac{6}{12}[/tex] = [tex]\frac{8}{12}[/tex] ÷ [tex]\frac{4}{4}[/tex] = [tex]\frac{2}{3}[/tex]
Answer:
[tex] \frac{1}{6} \frac{3}{4} = \frac{11}{12} [/tex]
Step-by-step explanation:
Step 1
Of course, you can't add two fractions if the denominators (bottom numbers) don't match. To get a common denominator, multiply the denominators together. Then we fix the numerators by multiplying each one by their other term's denominator.
Now you multiply 1 by 4, and get 4, then we multiply 6 by 4 and get 24.
Step 2
Since our denominators match, we can add the numerators.
4 + 18 = 22
The sum we get is
[tex] \frac{22}{24} [/tex]
Step 3
The last step is to reduce the fraction if we can.
To find out, we try dividing it by 2...
Are both the numerator and the denominator evenly divisible by 2? Yes! So we reduce it:
[tex] \frac{22}{24} \div {2} = \frac{11}{12} [/tex]
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