Answer:
Assuming a typo in the equation...
Should it be 6x^3-kx^2-5x+6 ?
divide (x-3) into this polynomial and you get 6x^2+(18-k)x+[3(18-k)-5] with remainder of
3[3(18-k)-5]+6 which must equal 0
3[3(18-k)-5]+6=0
3[54-3k-5]+6=0
3[49-3k]+6=0
3[49-3k]=-6
49-3k=-2
49+2=3k
51=3k
k=51/3=17
or more simply, use Mark M.'s method: f(3) must equal 0 so replace each x with 3 to get the value of k
Step-by-step explanation:
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