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b. y varies inversely with x. If y = 20 when x = 8, find x when y = -5.
Solution:​


Sagot :

Step-by-step explanation:

[tex]y = \frac{k}{x} [/tex]

[tex]20= \frac{k}{8} [/tex]

[tex]20(8) = k[/tex]

[tex]k = 160[/tex]

[tex] - 5 = \frac{160}{x} [/tex]

[tex] - 5x = 160[/tex]

[tex] \frac{ - 5x}{ - 5} = \frac{160}{ - 5} [/tex]

[tex]x = - 32[/tex]