Answer:
Solution :
[tex]x = \frac{11}{4} \\ x = - \frac{11}{4} [/tex]
Step-by-step explanation:
[tex]16 {x}^{2} - 121[/tex] is a difference of two squares. Therefore;
[tex]16 {x}^{2} - 121 = 0 \\ {(4x)}^{2} - {(11)}^{2} = 0 \\ (4x - 11)(4x + 11) = 0 \\ \\ 4x - 11 = 0 \\ 4x = 11 \\ \frac{4x}{4} = \frac{11}{4} \\ x = \frac{11}{4} \\ \\ 4x + 11 = 0 \\ 4x = - 11 \\ \frac{4x}{4} = \frac{ - 11}{4} \\ x = - \frac{11}{4} [/tex]
