Problem⤵️
[tex]( \frac{1}{4} + \frac{2}{5} ) - \frac{3}{5} [/tex]
Solution⤵️
[tex] \frac{1}{4} + \frac{2}{5} = n \\ \frac{?}{20} + \frac{?}{20} = n \\ (the \: lcm \: of \: 4 \: and \: 5 \: is \: 20) \\ (20 \div 4 = 5 \times 1 = 5) \\ (20 \div 5 = 4 \times 2 = 8) \\ \frac{8}{20} + \frac{5}{20} = \frac{13}{20} \: \\ \frac{13}{20} - \frac{3}{5} = n \\ \frac{13}{20} - \frac{12}{20} = \frac{1}{20}[/tex]
Final Answer⤵️
[tex]\frac{1}{20}[/tex]
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