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10. If (x-4) varies inversely as (y + 3) and x = 8 when y = 2, find x when y=-1.​


Sagot :

Step-by-step explanation:

[tex]x - 4 = \frac{k}{y + 3} [/tex]

[tex](8 - 4) = \frac{k}{(2 + 3)} [/tex]

[tex]4 = \frac{k}{5} [/tex]

[tex]4(5) = k[/tex]

[tex]k = 20[/tex]

[tex]x - 4 = \frac{20}{ (- 1 + 2)} [/tex]

[tex]x - 4 = \frac{20}{2} [/tex]

[tex]2(x - 4) = 20[/tex]

[tex]2x - 8 = 20[/tex]

[tex]2x = 20 - 4[/tex]

[tex]2x = 16[/tex]

[tex] \frac{2x}{ 2} = \frac{16}{2} [/tex]

[tex]x = 8[/tex]