QUESTION
the area of the rectangle is 3x² + 7x - 6, what is the length if the width is (x + 3)
SOLUTION
REMEMBER:
[tex] \green{given} = \begin{cases} 3x^{2} + 7x - 6 & \text{area} \\ x + 3 & \text{width}\end{cases}[/tex]
FINDING FOR THE LENGTH
[tex] \implies \: \: \huge{}^{3x^{2} + 7x - 6} \! / {}_{x + 3}[/tex]
[tex] \implies \large {}{(3x - 2)(x + 3)} \! / \large{}_{x + 3}[/tex]
[tex] \implies \large \: (3x - 2)[/tex]
FINAL ANSWER
[tex] \large\boxed{ \tt \: length \: = (3x - 2)}[/tex]
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