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Dimaunahanjacob11go
Answered

1. What is the area of the rectangle
whose length is (x + 5) and width is (x -5)? ​

Sagot :

OnekPHgo

Answer:

X^2 -25

Step-by-step explanation:

Area is length times width

A= (x-5)(x+5)

A= x2 -25, diff of two squares

Clye16go

Answer:

[tex]x^{2}[/tex]-25

Step-by-step explanation:

Simply do the multiplication method which is

  x + 5

x

  x - 5 is equal to ?

First, multiply +5 and -5 which results to -25

Next multiply +5 and x same as -5 and x which results to +5x and -5x

Then, multiply x and x which is equals to [tex]x^{2}[/tex]

Last add them all up then you get the answer of

[tex]x^{2}[/tex]-25

  x+5

x

  x-5

First term:+5 x -5 = -25

Second term:(+5 times x)  + (-5 times x)  = 0

Last term:x times x = [tex]x^{2}[/tex] thx.

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