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what are the three consecutive positive integers such that the sum of their squares is 245?​

Sagot :

sorry the last is wrong answer

the correct is

8,9,10

square of 8= 64

square of 9= 81

square of 10= 100

so 64+81+100= 245

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Answer:

8,9,10

Step-by-step explanation:

Let the numbers be x, x+1, x+2

Then,

X^2 +(x+1)^2 +(x+2)^2 =245

Simplify

X2 + x2 +2x+1+ x2+4x+4=245

Simplify by combining like terms

3x2+6x+5=245

3x2+6x-245+5=0

3x2+6x-240 =0 divide both sides by 3

X2+2x-80=0

Factor

(X+10)(x-8)=0

X=8,-10 disregard -10,instead use 8

The numbers are

8,9,10

Sana nakatulong ako :)