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A nail 2mm in diameter is embedded in a tire in which the gauge pressure is 1.8 bar. How much force tends to push the nail out?​

Sagot :

Converting the pressure from Bar to Pa.

1 Bar = 100,000 Pa

(1.8 Bar)(100,000 Pa / 1 Bar)

= 180,000 Pa

Converting the diameter from mm to m.

1 mm = 0.001 m

(2 mm)(0.001 m / 1 mm)

= 0.002 m

Converting the diameter to its radius.

Given

  • Diameter (d) = 0.002 m
  • Radius (r) = ?

r = d / 2

r = 0.002 / 2

r = 0.001 m

Calculating the area of the nail.

Given

  • Radius (r) = 0.001 m
  • Area (A) = ?

Use π = 3.14

A = πr²

A = (π)(0.001)²

A = 0.000001π

A = 0.00000314 m²

Calculating the force with pressure.

Given

  • Area (A) = 0.00000314 m²
  • Pressure (P) = 180,000 Pa
  • Force (F) = ?

F = PA

F = (0.00000314 m²)(180,000 Pa)

F = 0.5652 N

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