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the square root of 1 more than twice a certain number is 6. find the number

Sagot :

Step-by-step explanation:

the equation will be like this:

√1+2x=6

first we will get the square root of 1 which is 1

1+2x=6

then the next thing we will do is to transpose 1 to the right side or we will move the constant term to the right side and the numbers with variables to the left. if we will move 1 to the right, it will become negative because it was moved through the equal sign.

2x=(-1)+6

then add the constant terms

2x=5

after that, divide it all by 2 because in order to get the value of x, we have to remove its constant term which is 2.

2x÷2=5÷2

x=5/2 or 2.5