Answer:
a. [tex]p = \frac{kqr^2}{s}[/tex]
b. k = 3
c. p = 96
d. s = 2
Step-by-step explanation:
b. Find k if p = 40, q = 5, r = 4 and s = 6.
[tex]40 = \frac{k(5)(4^2)}{6}[/tex]
[tex]40 = \frac{80k}{6}[/tex]
Cross multiply
[tex]240 = 80k[/tex]
[tex]k = 240/80[/tex]
[tex]k = 3[/tex]
c. Find p when q = 8, r = 6 and s = 9.
[tex]p = \frac{3(8)(6^2)}{9}[/tex]
[tex]p = \frac{864}{9}[/tex]
[tex]p = 96[/tex]
d. Find s when p = 10, q = 5 and r = 2.
[tex]10 = \frac{5(s^2)}{2}[/tex]
[tex]10 = \frac{5s^2}{2}[/tex]
Cross multiply
[tex]20 = 5s^2[/tex]
[tex]4 = s^2[/tex]
[tex]s = \sqrt{4} = 2[/tex]
Note: s cannot be negative
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