Sagot :
SAMPLE SIZE
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Problem
- in your study, the size of your population is 5250 respondents. what is the size of your sample if you allow 5% margin of error?
Given
- N = 5,250.00
- e = 5%
- n = ?
Solution
Determine the sample size using the formula in which n is the sample size, N is the population and e is the acceptable sampling error
- [tex]\bold{Formula\:||\:Sample_{Size} = \frac{N}{1\:+\: {N}^{2} } }[/tex]
- [tex]\large\tt{\red{Sample_{Size}} = \frac{5,250}{1 \:+\: (5,250){(0.05)}^{2} } }[/tex]
Substitute the values of n and e to the formula and solve for the product at the denominator then simplify
- [tex]\large\tt{Sample_{Size} = \frac{N}{1\: + \:{N}^{2} }}[/tex]
- [tex]\large\tt{Sample_{Size} = \frac{5,250}{1 \:+ \:(5,250) (0.05)²}}[/tex]
- [tex]\large\tt{Sample_{Size} = \frac{5,250}{ 1 \:+ \:(5,250) (0.0025) }}[/tex]
- [tex]\large\tt{Sample_{Size} = \frac{5,250}{14.12}}[/tex]
- [tex]\underline{\large\tt\red{371.81= Sample_{Size}}}[/tex]
Final Answer
- Therefore, The size of your sample if you allow 5% margin of error is 371
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