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A car traveling at an average speed of 55 kph leaves Town A for Town B, at a distance of 120 km. At the same time, another car, traveling on the same highway at an average speed of 45 kph, leaves Town B for Town A. How many hours will they meet?

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Answer:

1.2hours

Step-by-step explanation:

Let x be distance from A to B

120-x be the distance from B to A

Know that,

v=d/t

Where v is the velocity

d is the distance

t is the time

The question is that they will meet the same time

Then,

1st equation

55=x/t

55t=x

2nd equation

45=(120-x) /t

Substitute

1 - 2 Equation

45=(120-55t) /t

45t=120-55t

100t=120

t=1.2 hours.

I remember this question in Dynamic Bodies.

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