Sagot :
Problem:
If y varies inversely as x and y = 2 when x = 8 find
A. constant of variation → k = 16
B. variation equation → y = 16/x
C. y when x = 16 → y = 1
Solution:
y = k/x
2 = k/8
2(8) = k
k = 16 → constant of variation
y = 16/x → equation of variation
y when x = 16
y = k/x
y = 16/16
y = 1