1. JP's age is twice the age of Reyna. The sum of their ages does not exceed 51.
2. Twice the sum of a number and 10 is 55.
3. Cut a 60 cm ribbon into two such that one part is one-third of the other.

Question

Desireemaemacaserogo Desireemaemacaserogo

English

Answered

1. JP's age is twice the age of Reyna. The sum of their ages does not exceed 51.
2. Twice the sum of a number and 10 is 55.
3. Cut a 60 cm ribbon into two such that one part is one-third of the other.

Sagot :

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Virgolicious25go Virgolicious25go · Answer 1

Answer:

1. 17 (age of Reyna), 34 (age of JP)

2. x=17.5

3. 1= 40 cm

2= 20 cm

Explanation:

1. Let

x be the age of Reyna

2x be the age of JP

x + 2x = 51

Solution:

x + 2x = 51

3x/3 = 51/3

x = 17 (age of Reyna)

2x = 2(17) = 34 (age of JP)

Checking:

17+34= 51 ✔️

2. 2(a number + 10)=55

Let

x be the number

Solution:

2(x+ 10)=55

2x + 20=55

2x=55-20 [transpost]

2x=35

2x/2=35/2

x=17.5

Checking:

2(x+ 10)=55

2(17.5+ 10)=55 [substitute the value of x]

2 (27.5)=55

55=55 ✔️

3. Solution:

60 x 1/3= 20 cm