Sagot :
Problem:
The length (l) of a violin string varies inversely as the frequency (f) of its vibrations. A violin string 14 inches long vibrates at a frequency of 450 cycles per second. Find the frequency of a 12 -inch violin string
Solution:
l = k/f
14 = k/450
14(450) = k
k = 6300
l = k/f
fl = k
f = k/l
f = 6300/12
f = 525 cycles per second