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Shessappygo
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What is the average speed of the car that covers a distance of (2y3—7y2 + 5y - 1) km in (2y—1) hour?

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Jonacriezldelacruzgo

Answer:

[tex]y^{2}-3y+1[/tex] (km/hr)

Step-by-step explanation:

speed = [tex]\frac{distance}{time}[/tex]

speed = [tex]\frac{(2y^{3} - 7y^{2} + 5y - 1) }{2y-1}[/tex]

speed = [tex]\frac{(2y-1)(y^{2}-3y+1) }{2y-1}[/tex]

speed = [tex]y^{2}-3y+1[/tex] (km/hr)

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