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Answered

solve the system of equation using substitution

x+3y=6
2x+6y-12=0​

Sagot :

Jolinabautre18go

Answer:

x+3y=6 2x+6y-12=0

2x= -6y+12

2

x=-3y+6

x+3y=6 x+3y=6

-3y+6+3y=6 x+3(0)=6

-3y+3y=6-6 x+0=6

y=0 x=6

(6,0)

checking

x+3y=6 2x+6y-12=0

6+3(0)=6 2(6)+6(0)-12=0

6+0=6 12+0-12=0

6=6 12-12=0

✓. 0=0

✓

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