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1. What is the percent by volume of a solution formed by
mixing 25mL of isopropanol with 45mL water?

i need the answer now plss help me​


Sagot :

Note: Isopropanol is the solute and water is the solvent.

Given:

[tex]\text{volume}_{solute} = \text{25 m L}[/tex]

[tex]\text{volume}_{solvent} = \text{45 m L}[/tex]

Required:

[tex]\% \: \text{by volume}[/tex]

Solution:

[tex]\% \: \text{by volume} = \frac{\text{volume}_{solute}}{\text{volume}_{solute} \: + \: \text{volume}_{solvent}} × 100[/tex]

[tex]\% \: \text{by volume} = \frac{\text{25 m L}}{\text{25 m L} \: + \: \text{45 m L}} × 100[/tex]

[tex]\boxed{\% \: \text{by volume} = 35.71\%}[/tex]