Sagot :
Problem:
If y varies inversely as x and y = 12 when x =⅔
Solution:
y = k/x
12 = k/2/3
12(2/3) = k
k = 8 → constant of variation
y = 8/x → equation of variation
y = k/x
12 = k/2/3
12(2/3) = k
k = 8 → constant of variation
y = 8/x → equation of variation