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Find the zeroes of the polynomial x³ - x² -25x + 25​

Sagot :

[tex] \large \mathcal{ANSWER:} [/tex] 

[tex] \large \boxed{x = \{-5, 1, 5\}} [/tex]

[tex] \large \mathcal{SOLUTION:} [/tex] 

[tex] \begin{array}{l} x^3 - x^2 - 25x + 25 = 0 \\ \\ \underline{\textsf{Factor by grouping.}} \\ \\ x^2(x - 1) - 25(x - 1) = 0 \\ \\ (x - 1)(x^2 - 25) = 0 \\ \\ (x - 1)(x - 5)(x + 5) = 0 \\ \\ \underline{\textsf{Equate each factor to 0.}} \\ \begin{aligned} x - 1 = 0 &\implies x = 1 \\ x - 5 = 0 &\implies x = 5 \\ x + 5 = 0 &\implies x = -5 \end{aligned} \\ \\ \therefore x =\{-5, 1, 5\} \end{array} [/tex]

[tex] \texttt \color{cyan} {\#CarryOnLearning} [/tex]