👤

Find the quadratic equation of the
roots 1/2 , 2/3?


Sagot :

Answer:

p(x)=6x^2-5x+16x

2

−5x+1

FORMULA:

QUADRATIC EQUATION P(X)=X^2-(SUM OF ZEROES)X +PRODUCT OF ZEROES.

EXPLANATION:

\alphaα =1/2

\betaβ =1/3

p(x)= x^2-x(\alpha+\beta)+\alpha\betax

2

−x(α+β)+αβ

p(x)=x^2-x(1/2+1/3)+(1/2)(1/3)x

2

−x(1/2+1/3)+(1/2)(1/3)

p(x)=x^2-x(5/6)+(1/6)x

2

−x(5/6)+(1/6)

p(x)=x^2-(5/6)x+(1/6)x

2

−(5/6)x+(1/6)

p(x)=6x^2-5x+16x

2

−5x+1

Answer:

work backwards to find the factors from the roots, then multiply the factors together.

[tex]y=x^{2} -\frac{7x}{6} +\frac{1}{3}[/tex]

Step-by-step explanation: