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A sculptor plans to make a sculpture on the shape of a rectangular prism.he wants the height and the width to be 5 inches less than the length.what should be the dimension of the prism if he wants to use a 250 cubic inches clay? ​

Sagot :

Answer:

The sculpture must be 5 inches wide, 5 inches tall, and 10 inches long.

Step-by-step explanation:

Let the dimensions of the sculpture be l, w and h.

[tex]\rm V = lwh[/tex]

Given:

  • [tex]\rm h= w = l - 5[/tex]
  • [tex]\rm V = 250[/tex]

Substitute the given value of the variables.

[tex]\implies \rm 250 = (l)(l-5)(l-5)[/tex]

[tex]\implies \rm 250 = (l^2-5l)(l-5)[/tex]

[tex]\implies \rm 250 = l^3-10l^2+25l[/tex]

[tex]\implies \rm l^3-10l^2 + 25l - 250 = 0[/tex]

[tex]\implies \rm (l - 10)(l^2+25) = 0[/tex]

[tex]\rm If \ l -10 = 0, then \ l= 10[/tex]

[tex]\rm If \ l^2+25 = 0,then \ l = 5i, which \ is\ unrealistic[/tex]

∴ l = 10.

Now, lets solve for the other dimensions.

[tex]\rm h = w = l - 5[/tex]

Substitute the value of l.

[tex]\implies \rm h = w = 10 - 5[/tex]

[tex]\implies \rm h = w = 5[/tex]

Therefore the sculpture must be 5 inches wide, 5 inches tall and 10 inches long.

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