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given, center C(3, -2)and radius (r)=2 units, find the equation of the circle in standard form​

Sagot :

Answer:

[tex](x - 3) ^{2} + (y + 2)^{2} = 4[/tex]

Step-by-step explanation:

The standard form of the equation of a circle can be written as:

[tex](x - h)^{2} + (y - k)^{2} = r^{2} [/tex]

where (h, k) is the point of the center of the circle and r is the radius of the circle.

Take note that we do not need to expand the equation. After substituting, we just have to simplify the right side.

[tex](x - 3) ^{2} + (y - ( - 2))^{2} = (2)^{2} [/tex]

[tex](x - 3)^{2} + (y + 2)^{2} = 4[/tex]

In writing lines and circles in standard form, always remember its template or formula.

Hope this helps!

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