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r varies inversely as d and r = 12 when d = 3. Find r when d = -9

Sagot :

INVERSE VARIATION

[tex] \\ [/tex]

[tex] \\ \bold{GIVEN: } \\ [/tex]

If r varies inversely as d and r= 12 when d= 3. Find r when d= -9.

[tex] \\ r = \frac{k}{d} \\ [/tex]

Evaluate the given values

[tex] \\ 12 = \frac{k}{3} \\ [/tex]

Multiply 3 to both sides

[tex] \\ (3)(12) = \frac{k}{3} (3) \\ [/tex]

Cancel both 3 from the right side

[tex] \\ (3)(12) = \frac{k}{ \cancel3} (\cancel 3) \\ [/tex]

multiply by 12

[tex] \\ \boxed{k = 36} \\ \\ [/tex]

Find the value of r when d= -9 and k= 36 from the first problem.

[tex] \\ r = \frac{k}{d} \\ [/tex]

Evaluate values

[tex] \\ r = \frac{36}{ - 4} \\ [/tex]

Divide

[tex] \\ \large\boxed{ \green{ \sf{r = - 4}}} \\ \\ [/tex]

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