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five times the square root of 1 less than a number is equal to 3 more than the number.Find the number. ​

Sagot :

Answer:

[tex]x = 17 \\ x = 2[/tex]

Step-by-step explanation:

[tex]5 \sqrt{x - 1} = x + 3[/tex]

[tex] {}^{2} (5 \sqrt{x - 1} = x + 3) {}^{2} [/tex]

[tex]25(x - 1) = (x + 3) {}^{2} [/tex]

[tex]25x - 25 = {x}^{2} + 3x + 3x + 9[/tex]

[tex]25x - 25 = {x}^{2} + 6x + 9[/tex]

[tex] {x}^{2} + 6x - 25x + 9 + 25 = 0[/tex]

[tex] {x}^{2} - 19x + 34 = 0[/tex]

[tex](x - 17)(x - 2)[/tex]

[tex]x = 17 \\ x = 2[/tex]