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Answered

Find the product of (b²+3) and (b²-3) ​

Sagot :

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Answer:

(b^2+3)×(b^2-3).

Answer: b^4-9

Solution:

Simplify the expression:

(b^2+3)×(b^2-3)

(b^2)^2-3^2

b^4-3^2

= b^4-9

Step-by-step explanation:

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