Sagot :
Answer:
1. b. 6.02 x 10^23 particles
2. c. 49.95%
[tex]\frac{32.065 g}{64.07 g/mole} = 0.49945\\ \\0.49945 *100 = 49.95%[/tex]
3. d. all of the above
4. d. mole
5. b. 6.02 x 10^23
Answer:
1. b. 6.02 x 10^23 particles
2. c. 49.95%
[tex]\frac{32.065 g}{64.07 g/mole} = 0.49945\\ \\0.49945 *100 = 49.95%[/tex]
3. d. all of the above
4. d. mole
5. b. 6.02 x 10^23