[tex] \large \red {\mathcal{Answer:}}[/tex]
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What is the radius of the circle in the equation (x-2)²+ (y-7)²=36?
A. -2
B. 2
C. 6
D. -7
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[tex] \large{ \green{ \mathcal{Explanation:}}}[/tex]
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The exact formula is:
[tex](x - h)^{2} + (y - k)^{2} = \sqrt{r} [/tex]
Whereas:
[tex] \large \: h = 2[/tex]
[tex] \large \: k = 7[/tex]
[tex] \large \: r = 36[/tex]
Solution:
[tex](x - h)^{2} + (y - k)^{2} = \sqrt{r} [/tex]
[tex](x - 2)^{2} + (y - 7) = \sqrt{36} [/tex]
[tex] \large \blue{ \boxed{ \boxed{(x - 2)^{2} + (y - 7)^{2} = 6}}}[/tex]
Therefore, the Final Answer is:
[tex] \huge{ \orange{ \boxed{ \tt{C. 6}}}}[/tex]
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#CarryOnLearning
