PROBLEM SOLVING
The square root of 5 more than twice a number is 7. Find the number.
The equation would be
√5 > 2x + 7
Solve for the value of x.
√5 > 2x + 7
√5 - 7 > 2x
√5 - 7 / 2 > 2x / 2
√5 - 7 / 2 > x or x = -7 + √5 / 2
[tex] \: [/tex]
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