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Changchangcharissego
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Problem solving
1. What percent (%) of nitrogen (N) in ammonia (NH3)?

2. Find the percentage composition of glucose(C6H12O6)?

3. The molar mass of water (H2O) is 18 grams per mole, how much is the % composition of oxygen?

4. Determine the percentage composition of carbon monoxide (CO).

(matinong sagot naman sana)
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Sagot :

Mgino5326go

Answer:

1.82.24% percent composition of N and 17.76% percent composition of H

SOLUTION:

14.007+1.008(3)=17.031

14.007)17.031X100=82.24414%

1.008+(3)/17.031X100=17.75586%

2.Molecular mass of glucose (C6H12O6)=6x12+1x12+6x6=72+12+96=180g.

% of carbon (C) in glucose =72/180x100=40

% of hydrogen (H) in glucose=12/180x100=6.66

% of oxygen (O) in glucose=96/180x100=53.33

3.

4.the percent composition of carbon monoxide, the molecule with a chemical formula of CO

42.88%CARBON

57.12%OXYGEN

Explanation:

SA number 3 wait po mejo nalilito ako

Wynner10010go

Answer:

[tex]3. mass\% = \frac{mass}{total \: mass} \times 100[/tex]

[tex]o =\frac{16}{18} \times 100 = 88.9\%[/tex]

16÷18=0.88888888889 x 100=88.888888889

O=88.9%

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