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Katarinachaenggo
Answered

The standard equation of a circle with the center at (h, k) and a radius of r units is (x – h)²+ (y – k)² = r². Given the cross section which is a circle, find the equation of a circle in standard form with center at (0, -5) and one point on the circle is (2, 3).
show your solution​

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Lovesickgirl69go

Answer:

Point of the center = (0, -5)

One point of the center = (2, 3)

Find the distance of two points.

d = √(x² - x¹)² + ( y² - y¹)²

d = √(2 - 0)² + ( 3 - (-5)²

d = √(2)² + (8)²

d = √4 + 64

d = √68

d = 2√17

The distance will be the radius of the circle.

Use the equation (x - h)² + (y - k)² = r² to find the standard equation of the circle.

(x - h)² + (y - k)² = r²

x² + (y + 5)² = (2√17)²

x² + (y + 5)² = (4)(17)

x² + (y + 5)² = 68

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