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A compound has a molar mass of 170.0 g/mol and an empirical formula of SiF3. The compound's molecular formula is ?​

Sagot :

Solution:

Step 1: Represent a molecular formula.

[tex]\text{molecular formula} = (\text{Si}\text{F}_{3})_{n}[/tex]

Step 2: Calculate the empirical mass.

empirical mass = (28.09 g/mol × 1) + (19.00 g/mol × 3)

empirical mass = 85.09 g/mol

Step 3: Divide the molar mass by the empirical mass.

[tex]n = \frac{\text{molar mass}}{\text{empirical mass}}[/tex]

[tex]n = \frac{\text{170.0 g/mol}}{\text{85.09 g/mol}}[/tex]

[tex]n = 2[/tex]

Step 4: Multiply the subscripts by the value of n to obtain the molecular formula.

[tex]\text{molecular formula} = (\text{Si}\text{F}_{3})_{2}[/tex]

[tex]\boxed{\text{molecular formula} = \text{Si}_{2}\text{F}_{6}}[/tex]

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