Answer:
[tex]\huge \boxed{x=1}[/tex]
Question
What is the value of [tex]x[/tex] in [tex]2(3x+2)=10[/tex]? Show your solution.
Solution
To get the value of x, first, we need to expand the equation by distributing 2 to the terms enclosed in parenthesis.
[tex]2(3x+2)=10\\2(3x)+2(2)=10\\6x+4=10[/tex]
Then, group the similar terms by transposing the constant terms (terms that contain an integer only) to the other side of the equation.
[tex]6x=10-4\\6x=6[/tex]
Divide both sides by 6 to remove the coefficient of [tex]x[/tex].
[tex]\dfrac{6x}{6}=\dfrac{6}{6}\\x=1[/tex]
Therefore, [tex]\bold{x=1}[/tex].
Short Solution
[tex]2(3x+2)=10\\2(3x)+2(2)=10\\6x+4=10\\ 6x=10-4\\6x=6\\ \dfrac{6x}{6}=\dfrac{6}{6}\\x=1[/tex]
To Check
Substitute [tex]x=1[/tex] to the original equation.
[tex]2(3(1)+2)=10\\2(3+2)=10\\2(5)=10\\10=10[/tex]
Since both sides have the same results, then, [tex]x=1[/tex] is correct.
How is it? (((o(*°▽°*)o)))
Happy learning!
