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Math

Answered

Dan has some P10 (x) and P5 (y) coins. The total amount of these coins is at most P750.00. Suppose there are 30 P5-coins. How many P10-coins are there?

Sagot :

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750 - 30(5)

750 - 150

= 500

500 ÷ 10

=50

answer: 50

P10 - coins

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