Answer:
a. Mathematical equation:
[tex] \sqrt{x + 3} = x + 1[/tex]
b. The number is either -2 or 1.
Solution:
For question b
[tex] \sqrt{x + 3} = x + 1 \\ {( \sqrt{x + 3}) }^{2} = {(x + 1)}^{2} \\ x + 3 = {x}^{2} + 2x + 1 \\ {x}^{2} + x - 2 = 0 \\ (x + 2)(x - 1) = 0 \\ x = - 2 \\ x = 1[/tex]
Checking:
If x = -2
[tex] \sqrt{x + 3} = x + 1 \\ \sqrt{ - 2 + 3} = - 2 + 1 \\ \sqrt{1} = - 1 \\ - 1 = - 1[/tex]
If x = 1
[tex] \sqrt{x + 3} = x + 1 \\ \sqrt{1 + 3} = 1 + 1 \\ \sqrt{4} = 2 \\ 2 = 2[/tex]
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