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Bleach solution contain sodium hypochlorite (NaOCl). How many moles NaOCl are in a 1500.0 g of 3.62% bleach of solution?




Sagot :

Solution:

Step 1: Calculate the mass of NaOCl.

[tex]\text{percent by mass} = \frac{\text{mass of NaOCl}}{\text{mass of solution}} × 100[/tex]

[tex]\text{mass of NaOCl} = \frac{\text{percent by mass}}{100} × \text{mass of solution}[/tex]

[tex]\text{mass of NaOCl} = \frac{3.62}{100} × \text{1500.0 g}[/tex]

[tex]\text{mass of NaOCl = 54.3 g}[/tex]

Step 2: Calculate the molar mass of NaOCl.

molar mass of NaOCl = (22.99 g/mol × 1) + (16.00 g/mol × 1) + (35.45 g/mol × 1)

molar mass of NaOCl = 74.44 g/mol

Step 3: Calculate the number of moles of NaOCl.

[tex]\text{moles of NaOCl} = \frac{\text{mass of NaOCl}}{\text{molar mass of NaOCl}}[/tex]

[tex]\text{moles of NaOCl} = \frac{\text{54.3 g}}{\text{74.44 g/mol}}[/tex]

[tex]\boxed{\text{moles of NaOCl = 0.729 mol}}[/tex]

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