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Answered

Find the three consecutive integers such that the sum of the first two integers is 47 more than the largest.

Sagot :

Freefrethalmazango

Answer:

48, 49, 50

Step-by-step explanation:

48 + 49 = 97

97 - 50 = 47

2x+1-47=(x+2)

2x−46=x+2

2x−46−x=2

x−46=2

x=2+46

x=48

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