Answer:
graph the line with slope 1/2 passing through the point(-5,-2)
find the slope of the line 5x+5y=3 write answer in simplest from
consider the line 2x-4y=4 what is the slope of a line perpendicular to this line. what jis the slope of a line parallel to this line
to graph the line, plot the point (-5,-2)
Now, since the slope is 1/2, that means that y increase by 1 when x increases by 2. So, starting at (-5,-2), move right 2 and up 1 and plot that point : (-3,-1).
Draw the line through those two points.
the slope of 5x+5y=3 is -1
The slope of 2x-4y=4 is 1/2. So is the slope of all lines parallel to it. The slope of all perpendiculars to it is -2.
1.A
2.B
3.D
4.C
5.D
Step-by-step explanation:
(baka sakali kaylangan mo)
algebra:
it says write the equation of the vertical line that passes through the point (7,-3). what do i need to start it off?
find the equation for the line with undefined slope and passing through the point (-1,-2). what do i need to start that off?
what equation do i use to find the slope-intercept?
whats the point-slope form?
any vertical line has an undefined slope and always has the form x = c, where c is a constant.
All you need is a point, then simply state it as x = 'the x of the given point'
so for your first one : x = 7
for the second x = -1
slope-intercept form looks like this
y = mx + b, where m is the slope and b is the y-intercept
e.g. y = 4x + 9
the slope is 4 and the y-intercept is 9
the point-slope form is one of the best ways to find the equation of a straight line, given the slope and a point
e.g. given the point (5,-3) and slope of 2/3, find the equation
y - (-3) = (2/3)(x - 5)
3(y+3) = 2(x-5)
3y + 3 = 2x - 10
you can now re-arrange it to end up with any version they ask for.
ANSWER:
my last line should have been
3y + 9 = 2x - 10
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