👤
Answered

integral (3-2x) dx using substitution​

Sagot :

Integral (3-2x)dx
Let u = 2x ; du = 2 dx

Integral (3-u)du/2
1/2 integral (3-u)du
1/2 (3u -u^2/2)
3u/2 - u^2 ; u=2x
3(2x)/2 - (2x)^2
3x-4x^2

The answer is 3x-4x^2

Go Training: Other Questions