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1.)The sides of the triangle are the following:4√8 cm, 4√18 cm, and 5√2 cm. find the perimeter of the triangle.
2.) Find the area of the triangle with width that is √48cm and length that is √125cm.
3.)The length of the edge of a cube is cube root of 7 cm. Find the volume of a cube.
4.) Square the term 6/√2.


Sagot :

Answer:

1)

Given:

[tex]a=4\sqrt{8} =8\sqrt{2} \\b=4\sqrt{18}=12\sqrt{2} \\c=5\sqrt{2\\}\\P=perimeter=?[/tex]

Solution:

[tex]P=a+b+c\\P=8\sqrt{2} +12\sqrt{2} +5\sqrt{2} \\P=25\sqrt{2}cm \\or\\P=35.36cm[/tex]

2)

Given:

[tex]w=\sqrt{48} =4\sqrt{3} \\l=\sqrt{125}=5\sqrt{5}\\A=area=?[/tex]

Solution:

[tex]A=\frac{1}{2}(lw)\\A=\frac{4\sqrt{3}*5\sqrt{5} }{2} \\A=\frac{20\sqrt{15} }{2} \\A=10\sqrt{15}cm^{2} \\or\\A=38.73cm^{2}[/tex]

3)

Given:

[tex]l=7\\V=volume=?[/tex]

Solution:

[tex]V=3a\\V=3(7)\\V=21cm^{3}[/tex]

4)

Solution:

[tex](\frac{6}{\sqrt{2} }) ^{2} =\frac{6^{2} }{(\sqrt{2})^{2} }= \frac{36}{2}=18[/tex]

Sure Answer