Sagot :
Answer:
1)
Given:
[tex]a=4\sqrt{8} =8\sqrt{2} \\b=4\sqrt{18}=12\sqrt{2} \\c=5\sqrt{2\\}\\P=perimeter=?[/tex]
Solution:
[tex]P=a+b+c\\P=8\sqrt{2} +12\sqrt{2} +5\sqrt{2} \\P=25\sqrt{2}cm \\or\\P=35.36cm[/tex]
2)
Given:
[tex]w=\sqrt{48} =4\sqrt{3} \\l=\sqrt{125}=5\sqrt{5}\\A=area=?[/tex]
Solution:
[tex]A=\frac{1}{2}(lw)\\A=\frac{4\sqrt{3}*5\sqrt{5} }{2} \\A=\frac{20\sqrt{15} }{2} \\A=10\sqrt{15}cm^{2} \\or\\A=38.73cm^{2}[/tex]
3)
Given:
[tex]l=7\\V=volume=?[/tex]
Solution:
[tex]V=3a\\V=3(7)\\V=21cm^{3}[/tex]
4)
Solution:
[tex](\frac{6}{\sqrt{2} }) ^{2} =\frac{6^{2} }{(\sqrt{2})^{2} }= \frac{36}{2}=18[/tex]
Sure Answer