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1. Kr gas occupies a volume of 1.75 L at 25.0°C. Determine the volume of the gas if the temperature is increased to 50.0°C

2. Helium occupies a volume of 3.80 Liters at -45°C. What volume will it occupy a 45°C?

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Babzkigo

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Problem:

1. Kr gas occupies a volume of 1.75 L at 25.0°C. Determine the volume of the gas if the temperature is increased to 50.0°C

Note:

We must convert Celsius to kelvin first before solving any gas law problem

25 + 273 = 298 Kelvin

50 + 273 = 323 Kelvin

Given Data:

V₁ ( initial volume ) = 1.75 L                    V₂ ( Final volume ) = ? unknown

T₁  ( initial temperature ) = 298 K           T₂ (Final temperature ) = 323 K

Solution:

We can use the formula V₂ = V₁T₂/T₁

V₂ = V₁T₂/T₁

    = 1.75 L × 323 K / 298 K

    = 1.9 L

Answer:

the final volume is 1.9 Liters

  • This can be best explain in Charles' Law wherein he states that volume and kelvin temperature of gas is directly proportional. When temperature increases, volume also increases.

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