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In a science laboratory, you rub a glass rod with silk, placing a 25-nC positive charge on it.
Calculate the force on the rod due to the Earth’s magnetic field (5 10−5 ), if you throw it
with a horizontal velocity of 15 m/s west.


Sagot :

The force on the rod : F = 1.875 x 10 ⁻¹¹ N

Further explanation

The magnetic force on a moving charge can be formulated :

F = qvB sin θ

v = the velocity of a charge, m/s

B = the magnetic field, T

F = magnetic force, N

q = charge, C

θ = the angle between the directions of v and B

The magnetic force F is perpendicular to the plane formed by v and B

The direction can be determined by the right-hand rule method

  • the thumb ⇒ v
  • the fingers ⇒ B
  • the palm ⇒ F

Given

Charge = 25 nC = 25 x 10⁻⁹C

The Earth’s magnetic field =5 x 10⁻⁵ T

Required

The force

Solution

By using the right-hand rule method, we can see that the angle-θ between the velocity(west) and the direction of the field(north) is 90º

The magnetic force

F = 25 x 10⁻⁹C x 15 m/s x 5 x 10⁻⁵ T x sin 90

F = 1.875 x 10 ⁻¹¹ N

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