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The sum of four consecutive even integer is 2 more than five times the first integer. Find the smallest integer


Sagot :

Answer:

10

Step-by-step explanation:

2X = 1st integer

2(X + 1) = 2nd integer

2(X + 2) = 3rd integer

2(X + 3) = 4th integer

2X + 2(X+1) + 2(X+2) + 2(X+3) = 2 + 5(2X)

2X + 2X + 2 + 2X + 4 + 2X + 6 = 2 + 10X

8X + 12 = 2 + 10X

10X - 8X = 12 - 2

2X = 10

X = 5

Since, the smallest integer is the 1st integer where it is 2X, then the value of the smallest integer is 10.