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Function or not function = Show your solution

1. 3x+y= 4
2. x²+y²= 4


Nonsense=Report​


Sagot :

FUNCTION OR NOT FUNCTION

1. 3x+y= 4

FUNCTION

  • The rule 3x+y= 4 is a function because if y can be expressed in terms of x , anf there is only one value of y for one value of x.

  • If x = 1 , then substitute in thr equation, then the value of y would be;

3x+y= 4

[tex]3(1) + y = 4[/tex]

[tex]3 + y = 4[/tex]

[tex]3 - 3 + y = 4 - 3[/tex]

[tex]y = 1[/tex]

2. x²+y²= 4

Not Function

Solution

The relation is not a funtion because if y can be expressed in terms of x, abd there is more than one value of y for one value of x.

[tex]x {}^{\red2} +\red y {}^{\red2} \red - \red4 \\ [/tex]

[tex] {x}^{\red2} \red+ y \red+ x {}^{\red2} = \red4( \red- x {)}^{\red2} [/tex]

[tex]y {}^{\red2} = \red4 \red- x {}^{\red2} [/tex]

[tex]y = \red± \sqrt{\red4 \red- \red2 {}^{\red2} } [/tex]

Notice that for every value of x, there are two values of y,Find th value of y if x=0

[tex]y = \green± \sqrt{\green4 \green- x {}^{\green2} } [/tex]

[tex]y = \green± \sqrt{\green4 \green- \green0 {}^{\green2} } [/tex]

[tex]y = \green± \sqrt{\green4} [/tex]

[tex]y = \green±\green2[/tex]