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How many grams of NaOH
would be required to prepare
800 grams of a 40% by mass
NaOH solution?
O 340 g
O 320 g
M
O 310 g
0
350 g​


Sagot :

Solution:

[tex]\text{mass percent} = \frac{\text{mass}_{\text{NaOH}}}{\text{mass}_{solution}} × 100[/tex]

[tex]\text{mass}_{\text{NaOH}} = \frac{\text{mass percent}}{100} × \text{mass}_{solution}[/tex]

[tex]\text{mass}_{\text{NaOH}} = \frac{40}{100} × \text{800 g}[/tex]

[tex]\boxed{\text{mass}_{\text{NaOH}} = \text{320 g}}[/tex]

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