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4. Calculate the molar concentration of a 45% aqueous CaCl2 solution whose density is
1.10 g/ml.​


Sagot :

The molar concentration : 4.46 M

Further explanation  

The concentration of a substance can be expressed in several quantities such as moles, percent (%) weight/volume,), molarity, molality, parts per million (ppm) or mole fraction. The concentration shows the amount of solute in a unit of the amount of solvent.  

Molarity shows the number of moles of solute in every 1 liter of solution or mmol in each ml of solution  

M = n : V  

Where  

M = Molarity , M  

n = number of moles of solute, mol  

V = Volume of a solution, L  

Given

% mass = 45% CaCl₂

density = ρ = 1.1 g/ml

Required

The molarity

Solution

mass CaCl₂ :

= % mass x density

= 0.45 x 1.1 g/ml

= 0.495 g/ml

mol CaCl₂(molar mass : 110,98 g/mol) :

= 0.495 g/ml : 110.98 g/mol

= 0.00446 mol/ml

in 1 L solution :

= 4.46 mol/L

So the molar concentration = 4.46 M

Or we can use the simple formula :

[tex]\tt M=\dfrac{\%mass\times \rho\times 10}{molar~mass}\\\\M=\dfrac{45\times 1.1\times 10}{110.98}}\\\\M=4.46~mol/L[/tex]

Learn more  

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