Answer:
[tex]x^3-3x^2+3x-1[/tex]
Step-by-step explanation:
[tex](x-1)^{3-0}\\(x-1)^3\\(x-1)(x-1)(x-1)\\((x)(x)+(x)(-1)+(-1)(x)+(-1)(-1))(x-1)\\(x^2-x-x+1)(x-1)\\(x^2-2x+1)(x-1)\\(x^2)(x)+(x^2)(-1)+(-2x)(x)+(-2x)(-1)+(1)(x)+(1)(-1)\\x^3-x^2-2x^2+2x+x-1\\x^3-3x^2+3x-1[/tex]
